In a competitive exam Ram got 10 less than Shyam who got 25 more than Mohan and Mohan got 20

let Java's marks be: x
then mohan's marks= (80/100)*x
Shyam's marks= (125/100)*(80/100)*x
Ram's marks = (90/100)*(125/100)*(80/100)*x=360
on solving we get x=400(java's marks)
java's pecentage = (400/500)*100= 80

correct me if I am wrong
8 years agoHelpfull: Yes(9) No(1)
a)
let j=100, m=80, s=100, r=90
since 90=360
then 100=400
jawa%=400*100/500=80
8 years agoHelpfull: Yes(4) No(0)
Given, marks of Ram = 360.
Then, according to the given data,
=> 360 = 90% of Shyam
=> Shyam = 360 * 10 /9 = 400

And, Shyam = 125% of Mohan
=> 400 = 125/100 * Mohan
=> Mohan = 400 * 100/125 =80 * 4= 320

Mohan = 80% of Java.
=> 320 = 80/100 *Java
=> Java = 320 * 100 / 80 = 400
Therefore, Java's percentage = 400/500 * 100 = 80%
7 years agoHelpfull: Yes(4) No(0)
Ram=Shyam(90/100). ....(1)
Shyam=Mohan(125/100) .....(2)
Mohan=Jawa(80/100) ....(3)
Ram's marks=360
therefore , From (1) we get Shyam's Marks=400
From (2) , We get Mohan's Marks=320
and From (3), we get Jawa's marks=400
Hence Java's percentage=80%
8 years agoHelpfull: Yes(3) No(0)
77%
as given ram got 72% , so shyam got 82% , mohan got 57% and java got 77%
option D..none of these
8 years agoHelpfull: Yes(0) No(1)
wali thats wrong ...according to your solution u r making mohan marks as 80% of java's marks nd thats not the question so all equations r wrong
8 years agoHelpfull: Yes(0) No(0)

In a competitive exam. Ram got 10% less than Shyam who got 25% more than Mohan and Mohan got 20% less than Jawa. If the marks were 500 and Ram got 360.What was Java's percentage.
a)80
b)64
c)72
d)None of these