In a competitive exam. Ram got 10% less than Shyam who got 25% more than Mohan and Mohan got 20% less than Jawa. If the marks were 500 and Ram got 360.What was Java's percentage.
a)80
b)64
c)72
d)None of these

• ram got 360
  which is 72%
  shyam=82%
  mohan=57%
  java=77%
  ans is none of these
• 12 years agoHelpfull: Yes(15) No(12)
• let Java's marks be: x
  then mohan's marks= (80/100)*x
  Shyam's marks= (125/100)*(80/100)*x
  Ram's marks = (90/100)*(125/100)*(80/100)*x=360
  on solving we get x=400(java's marks)
  java's pecentage = (400/500)*100= 80
  
  correct me if I am wrong
  
• 9 years agoHelpfull: Yes(9) No(1)
• a)
  let j=100, m=80, s=100, r=90
  since 90=360
  then 100=400
  jawa%=400*100/500=80
• 9 years agoHelpfull: Yes(4) No(0)
• Given, marks of Ram = 360.
  Then, according to the given data,
  => 360 = 90% of Shyam
  => Shyam = 360 * 10 /9 = 400
  
  And, Shyam = 125% of Mohan
  => 400 = 125/100 * Mohan
  => Mohan = 400 * 100/125 =80 * 4= 320
  
  Mohan = 80% of Java.
  => 320 = 80/100 *Java
  => Java = 320 * 100 / 80 = 400
  Therefore, Java's percentage = 400/500 * 100 = 80%
• 8 years agoHelpfull: Yes(4) No(0)
• Ram=Shyam(90/100). ....(1)
  Shyam=Mohan(125/100) .....(2)
  Mohan=Jawa(80/100) ....(3)
  Ram's marks=360
  therefore , From (1) we get Shyam's Marks=400
  From (2) , We get Mohan's Marks=320
  and From (3), we get Jawa's marks=400
  Hence Java's percentage=80%
• 9 years agoHelpfull: Yes(3) No(0)
• 77%
  as given ram got 72% , so shyam got 82% , mohan got 57% and java got 77%
  option D..none of these
  
• 9 years agoHelpfull: Yes(0) No(1)
• wali thats wrong ...according to your solution u r making mohan marks as 80% of java's marks nd thats not the question so all equations r wrong
• 9 years agoHelpfull: Yes(0) No(0)