By walking at 3/4th of his usual speed, a man reaches office 20 minutes later than usual. What is his usual time?

• let T be the usual time.
  time spent=4T/3
  therefore, 4T/3=T+20
  4T=3T+60...therefor T=60min
• 9 years agoHelpfull: Yes(0) No(2)
• usual speed and time let say s,t
  st=3/4s(t+20)
  4st=3st+15s
  t=15
  so ans=15min
• 8 years agoHelpfull: Yes(0) No(2)
• Let the original speed be S and time be T
  If new speed=S×
  3
  4
  , then new time would be T×
  4
  3
  . (D = ST = Constant).
  Given,
  3T
  4
  −T=
  20T
  3
  
  ⇒ T=60 minutes
  = 1 hour
• 7 years agoHelpfull: Yes(0) No(0)