Linda left home and drove for 2 hours. She stopped for lunch then drove for another 3 hours at a rate that is 10 mph higher than the rate before she had lunch. If the total distance Linda travelled is 230 miles, what was the rate before lunch?

• home to lunch - 2hrs , x miles per hr
  after lunch- 3 hrs, (x+10)miles per hr
  2x + 3(x+10)=230
  on solving:
  x=40 miles per hr
• 10 years agoHelpfull: Yes(1) No(1)