The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A. 8, 20, 28 B. 16, 28, 36

C. 20, 35, 45 D. None of these

• Let the present ages are 4x, 7x, 9x.
  => (4x-8) + (7x-8) + (9x-8) = 56
  => 20x = 80
  => x = 4
  
  So their present ages are: 16,28,36
• 8 years agoHelpfull: Yes(1) No(0)
• b is satisfies the best solution
• 9 years agoHelpfull: Yes(0) No(0)