Find the sum of roots of the equation
root(x+7)=xroot(x+7)

• root(x+7)=x*root(x+7)
  
  by squaring on both sides....
  
  (x+7)=(x^2) * (x+7)
  by cancelling both sides
  1= x^2
  the roots are x= 1 and -1
  the sum of roots = 1+(-1)=0
  
  
  
  
• 10 years agoHelpfull: Yes(14) No(8)
• squaring both sides
  x+7=x^2(x+7)
  x+7=x^3+7x^2
  x^3+7x^2-x-7=0
  by hit and trial
  x=1
  it will satisfy
  now divide the equation with x-1
  x^3+7x^2-x-7/x-1 =x^2+8x+7
  solving the quadratic eqation will give roots -7,-1
  now sum will be 1+(-7)+(-1)=-7
  Answer=-7
• 10 years agoHelpfull: Yes(12) No(8)
• squaring on both the sides
  (x+7)=x^2 (x+7)
  (x+7) - x^2(x+7) = 0
  (x+7) [1 - x^2)=0
  x = -7 , x = 1
  sum = -7+1 = -6
• 10 years agoHelpfull: Yes(8) No(11)
• squaring on both sides
  x+7=x^2(x+7)
  x^2(x+7)-(x+7)=0
  (x^2-1)(x+7)=0
  the roots are x=1 & -1 , x=-7
  sum of the roots are 1+(-1)+(-7)= -7
• 10 years agoHelpfull: Yes(5) No(5)
• rootI(x+7)=xroot(x+7)
  squaring we get
  x+7=x^2(x+7)
  (x+7)(x^2-1)=0
  x+7=0 or x^2-1=0
  x=-7 or x^2=1
  x=-7 or x=1 or x=-1
  now put the all values in given equation root(x+7)=xroot(x+7)
  we get x=-1 does not satisfy the equation
  so value will be x=-7 and 1
  hence, sum of roots=1-7= -6
  
• 10 years agoHelpfull: Yes(4) No(8)