GENPACT Company Numerical Ability Age Problem

Ana is 5 years more than Jack. The sum of their ages is 29. Find the ages of Ana and Jack.

Read Solution (Total 4)

Ages of Ana's= 17; Jack= 12

Let Jack's age = x
And Ana's age, y = x+5---->(1)
Sum of their ages, x+y = 29----->(2)
substitute equation 1 in 2,
x+(x+5)=29
2x+5=29
2x=29-5
2x=24 ==>x=12(Jack's age)
Substitute x value in equation 1,
y= x+5
y= 12+5
y=17(Ana's age)
12 years agoHelpfull: Yes(5) No(0)

A=J+5 i.e A-j=5 --1
A+J=29 --2
FROM 1 AND 2
A=17 J=12
10 years agoHelpfull: Yes(0) No(0)
ANA=JACK+5
A+J=29
J+5+J=29
2J=24
J=12,A=17
9 years agoHelpfull: Yes(0) No(0)
jack=x ; ana=5+x ==>ana+jack=29
5+x+x=29 ; 2x=29-5=24 ;x=242=12 ;x=12
jack=12; ana=5+12=17.
9 years agoHelpfull: Yes(0) No(0)

GENPACT Other Question

Pete, Bryan and Philip are cousins. Pete’s age is one-third of Bryan and Philip is five years elder than Bryan. If the sum of the age of the cousins is 40, find the ages of each. Tina is 3 years younger than Tom. The ages are in the ratio 2:3. Find their ages.