GENPACT
Company
Programming
Technical
The difference between the ages of A and B is 10 years. Ten years ago, A was twice as old as B. Find the age of A, 10 years hence.
a.20 years
b.30 years
c.40 years
d.50 years
Read Solution (Total 3)
-
- ANS:-c
given that A-B=10 ->(1)
A-10=2(B-10)
A=2B-10 ->(2)
by solving 1&2
we get A=30,B=20
After 10 years age of A is 40 years - 12 years agoHelpfull: Yes(5) No(0)
- given
A-B=10 ------- 1
10 yrs ago
A-10=2(B-10)
A-2B=-10----- 2
from eq 1 and eq 2
B=20 A=30
age of A 10 yrs hence = 40
- 12 years agoHelpfull: Yes(1) No(0)
- ans:b
A-B=10(given)
also given
A-10=2(B-10)........(a)
A+10=?
Then A=B+10........(1)
put 1 in a
==>B=10
and A=20
Then A+10=30
- 11 years agoHelpfull: Yes(1) No(3)
GENPACT Other Question