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The age of a man is twice the sum of the ages of his two sons. Five years hence, his age will be 16 years more than the sum of the ages of his sons. What is the father's present age?
a.42 years
b.40 years
c.45 years
d.Inadequate data

Read Solution (Total 2)

Ans:-42 years
let man's age be m and sons ages will be x&y
given that m=2(x+y)=x+y=m/2
m+5=x+5+y+5+16
m=x+y+21
m=m/2+21
m=42
12 years agoHelpfull: Yes(4) No(1)

let man age be M
let sons age be A,B
given
M=2(A+B)----- 1
5 yrs hence
age of man is M+5 ---- 2
given tat
age of man after 5 yrs is A+5+B+5+16 ----- 3
equating eq 2 and eq 3
M+5=A+5+B+5+16
substituting eq 1 in above
we get A+B=21
but we know
M=2(A+B)=2(21)=42
so M=42
11 years agoHelpfull: Yes(1) No(1)

GENPACT Other Question

At present the son's age is same as was his father's age at the time of his birth. If father's age is 48. Find the son's age after 4 years from now.
a.30 years
b.24 years
c.28 years
d.Inadequate data Four years ago, the ratio of ages of Purple and Blue was 2:3, respectively. If the sum of their present ages is 28. Compute the ratio of their ages four years hence.
a.1:5
b.2:5
c.3:5
d.4:5