IBM
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Numerical Ability
Age Problem
The present ages of A and B are as 6 : 4. Five years ago their ages were in the ratio 5 : 3. Find their present ages.
Read Solution (Total 5)
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- Let their present ages be 6x & 4x
5 years ago, their ages were (6x-5) and (4x-5)
Now it is said that five years ago their ages were in the ratio 5:3.
So that means (6x-5) and (4x-5) must be in the ratio 5:3
Hence, (6x-5)/(4x-5) = 5/3
On solving we get x=5
So their present ages are 6x & 4x i.e., 6*5=30 and 4*5=20
Answer: 30, 20 - 10 years agoHelpfull: Yes(8) No(0)
- A's age is 30 and B's age is 20
- 11 years agoHelpfull: Yes(1) No(0)
- answer :- a = 30
b = 20 - 10 years agoHelpfull: Yes(1) No(0)
- 3(6x-5)=5(4x-5)
x=5
A=30 B=20 - 9 years agoHelpfull: Yes(1) No(0)
- age of A is 30 and age of B is 20
- 6 years agoHelpfull: Yes(0) No(0)
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