There are 3 ants at 3 different corners of a triangle. They randomly start to move towards each other. What is the probability that they will colloid?
A) 75 B) 100 C) 50 D) 25 E) None
Answer please. . .

• To prevent collision ants have to move in this particular way
  A-->B,B-->C,C-->A ; probability=(1/2*1/2*1/2)
  
  in opp direction
  A-->C,C-->B,B-->A ; probability=(1/2*1/2*1/2)
  
  probability that the ants doesnt coincide=
  (1/2*1/2*1/2)+(1/2*1/2*1/2)
  =(1/8)+(1/8)
  
  Probability that they will collide = {1-(1/4)} *100
  answer = 75
• 9 years agoHelpfull: Yes(18) No(0)
• Question: Three ants are sitting at the three corners of an equilateral triangle. Each ant starts randomly picks a direction and starts to move along the edge of the triangle. What is the probability that none of the ants collide?
  
  Answer: So let’s think this through. The ants can only avoid a collision if they all decide to move in the same direction (either clockwise or anti-clockwise). If the ants do not pick the same direction, there will definitely be a collision. Each ant has the option to either move clockwise or anti-clockwise. There is a one in two chance that an ant decides to pick a particular direction. Using simple probability calculations, we can determine the probability of no collision.
  
  P(No collision) = P(All ants go in a clockwise direction) + P( All ants go in an anti-clockwise direction) = 0.5 * 0.5 * 0.5 + 0.5 * 0.5 * 0.5 = 0.25
  
  So ans is 1-0.25=0.75
• 9 years agoHelpfull: Yes(11) No(0)
• They collide when all three anti clockwise or all three clockwise .... now everyant has 2 options --clock or anticlockwise.. hence 2/(2*2*2)= 0.25 !
• 9 years agoHelpfull: Yes(2) No(6)
• what is the correct answer...if not getting answers den hw cn we knw about ri8 answers..:-(
• 9 years agoHelpfull: Yes(2) No(0)
• every ant has two paths...................
  so no. of selecting path=2.................n(E)
  total no possible cases is 2*2*2=8..........n(s)
  
  Probability=(2)/8................................= 0.25
• 9 years agoHelpfull: Yes(0) No(0)