what is the positive value of : 121*25+625*12+144*11
A) less than 11*25*12
B) less than 2*11*25*12
C) less than 3*11*25*12
D) Greater than or equal to 3*11*25*12

• D)
  as the solutin is 12109 so 3*3300 gives 9900 and 12109 is greatr than this
• 9 years agoHelpfull: Yes(7) No(1)
• Consider a=11,b=25,c=12 and given expression as (a^2)*b+(b^2)*c+(c^2)*a and all options are in terms of a*b*c.
  So divide (a^2)*b+(b^2)*c+(c^2)*a by a*b*c.
  next you will get (a/c)+(b/a)+(c/b)
  Now substitute a,b,c values
  then approximately 0.9+2.08+0.4>3
  Hence the answer is d.
  D) Greater than or equal to 3*11*25*12
• 8 years agoHelpfull: Yes(6) No(0)
• is there any shortcut to solve this kind of questions ?
• 9 years agoHelpfull: Yes(2) No(0)
• a) 12109
• 9 years agoHelpfull: Yes(1) No(2)
• option D is correct
  25(121+300)+1584=12109
  now take options verification
  
• 9 years agoHelpfull: Yes(1) No(1)
• Answer will be 3 and as it is not given in the options,hence it will be none.
  Take any number divisible of 6 and add 4 and 5 respectively,when u add those and divide by 6 the remainder for all the cases are coming to be 3.
• 9 years agoHelpfull: Yes(1) No(0)