Find the scale factor, the ratio of the perimeters, and the ratio of the areas of two regular octagons that have sides of lengths 21 and 28, respectively.

• scale factor z d ratio of 2 lengths i.e., 21:28=7:8
  ratio of perimeter (octagons) : 8a:8b=8*21:8*28=7:8
  ratio of areas (octagons): (2+2sqrt(2))a^2:(2+2sqrt(2))a^2=7:8
• 11 years agoHelpfull: Yes(1) No(1)
• area of a ocagon is a^2(2+2sqrt(2))
  perimeter of a octagon is 8.a
• 11 years agoHelpfull: Yes(0) No(2)
• scale factor = 21:28 = 3:4
  perimeter ratio 3:4
  area ration = 9:16
• 7 years agoHelpfull: Yes(0) No(0)