10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
A. 90 B. 145
C. 150 D. 225

• 1 man,s 1 day work =1/100
  let 1 woman's 1 day work = 1/x
  so
  (1/10)+(15/x)=(1/6)
  x=225
  
• 12 years agoHelpfull: Yes(21) No(2)
• 1man 1 day= 1/100
  (10man+15woman) 1day = 1/6
  10/100+15woman1day = 1/6
  15 woman 1day = 1/6 - 1/10
  1 woman 1 day = 1/15 (1/6 - 1/10) = 1/225 = 225ans.
• 12 years agoHelpfull: Yes(12) No(1)
• 10x+15y=1/6 ............(1) (x=men,y=women)
  x=1/100
  //put x value in equation (1)
  15y=1/6-1/10
  y=225
• 7 years agoHelpfull: Yes(6) No(0)
• one man's one day work= 1/100
  10 mens +15 women = 1/6
  15 women 1 day work = 1/6 - 10/100 ( total man/ man day work)
  1 woman 1 day work = 1/15*15 = 1/225
  so for onw woman it takes 225 days to complete a work
• 7 years agoHelpfull: Yes(1) No(0)
• 1men takes 100 days
  10men takes 10days
  then
  1/10+15/x=1/6
  x=225
• 7 years agoHelpfull: Yes(0) No(0)
• 10M+5W =1/6 (per day work)
  1M work = 1/100
  1w work =10/100+5w=1/6
  1w work =225
• 5 years agoHelpfull: Yes(0) No(0)
• 10m+15w = 6 days
  1 man = 100 days
  10 men in 10 days
  15 women = 10*6/4=15 days
  One women = 15*15 =225 days
• 5 years agoHelpfull: Yes(0) No(0)