A,B, and C can complete a piece of work in 24,6 and 12 days respectively. Working together , they will complete the same work in
A. 1/24 day B. 7/24 day
C. 3x3/7 days D. 4 days

• combined 1 day work
  =(1/10+1/12+1/15th part of the work
  =7/24 th part of the work
  time of completion by working together=1/(7/24)=3*3/7 days
  ans: option C
• 10 years agoHelpfull: Yes(15) No(2)
• Sol: Given A in 24 days,
  B in 6 days and
  C in 12 days
  then A in 1 day is 1/24,B in 1 day is 1/6 and C in 1/12
  
  therefore together they can complete the same work in
  1/24 + 1/6 + 1/12 = 7/24
• 11 years agoHelpfull: Yes(9) No(15)
• A's one day work=1/24
  B's one day work=1/6
  c's one day work=1/12
  
  then all together A+B+C one day work = (1/24+1/6+1/12)
  = 7/24
  all together complete the the work in=24/7 days = 3*3/7 days
• 7 years agoHelpfull: Yes(1) No(0)
• Option B
  The total work will be LCM(24,6,12)=24
  A's work = 24/24=1 unit/day
  B's work = 24/6 =4 units/day
  C's work = 24/12=2 units /day
  so 1 day work = 7 units/day but total units =24
  i.e.., work = 7/24
• 6 years agoHelpfull: Yes(0) No(0)