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Numerical Ability
Time and Work
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is
A. 1/4 B. 1/10
C. 7/15 D. 8/15
Read Solution (Total 6)
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- Find the LCM of (15 and 20) units=60 units
A's work for 4days=16 units
B's work for 4days=12 units
Total work for both in 4 days=16+12=28
Hence the fraction of the work that is left=32/60=8/15 - 13 years agoHelpfull: Yes(22) No(11)
- 5/18
(A+B) work=1/15+1/20=7/60
4 days work=28/60
left work=1-28/60=32/60=8/15 - 11 years agoHelpfull: Yes(15) No(1)
- A+B can do 1/15 +1/20 = 7/60
for 4 days working together then work done is 4*7/60 =7/15
the work left is = 1-7/15 = 8/15 - 8 years agoHelpfull: Yes(6) No(0)
- Total work done by them in one day = 1/15 + 1/20 = 7/60
Total work done in 4 days = (7*4)/60
Work left = 1-28/60 = 8/15 - 7 years agoHelpfull: Yes(0) No(0)
- A----15 days ,B----- 20 days. LCM(15,20)= 60. A----4 unit. B----- 3 unit. A+B= 28. Work that is left= (60-28)/60= 32/60= 8/15
- 7 years agoHelpfull: Yes(0) No(0)
- A can do work in 15 days
B can do the same work in 20 days
then work done by both in one day = 1/15+1/20=7/60.
Work done by both in 4 days = 4*1/60= 28/60=7/15
then the remainig work = 1-7/15= 8/15 ans - 6 years agoHelpfull: Yes(0) No(0)
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