A and B together can do a piece of work in 30 days.A having worked for 16 days, B finishes the remaining work in 44 days. In how many days shall B finish the whole work alone?
A. 30 days B. 40 days
C. 60 days D. 70 days

• Answer: Option C
  
  Explanation:
  
  Let A's 1 day's work = x and B's 1 day's work = y.
  
  Then, x + y = 1 and 16x + 44y = 1.
  30
  Solving these two equations, we get: x = 1 and y = 1
  60 60
  B's 1 day's work = 1 .
  60
  Hence, B alone shall finish the whole work in 60 days.
• 12 years agoHelpfull: Yes(8) No(19)
• Let, A's 1 day's work be x and that of B's be y.
  Given that, A and B together can finish the work in 30 days.
  According to the question, A's and B's 1 day's work=1/30.
  So, x+y=1/30........ (1)
  Again,
  16x+44y=1............(2) [ As A's 16 day's work=16x;B's 44 day's work=44y]
  Solving equation (1) and (2) we get,
  y=1/60 which is B's 1 day's work.
  Therefore, B alone can do it in 60 days.
  Hence, Answer is (C.) 60 days.
• 9 years agoHelpfull: Yes(8) No(0)
• A+B=30 days. (A=30, B=30 Average =30+30/2 =60/2= 30 days)
  A = 16 days
  Remaining finish by B=44 days
  when B alone complete whole work = 16+44 =60 days
  
  
• 9 years agoHelpfull: Yes(6) No(6)