Huawei
Exam
Numerical Ability
Sequence and Series
find the odd no out of:- 396, 462, 572, 396, 427, 671, 264
a. 396 b. 427 c. 671 d. 264
this is the question asked in huawei techlology please solve this please..
Read Solution (Total 12)
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- b. 427
in others for a no. XYZ ,
X+Z = Y follow.
OR, others are multiple of 11 except 427 . - 10 years agoHelpfull: Yes(41) No(1)
- Addition of all the three digits of a number is an even number except 427.
Elaboration:
3+9+6=18
4+6+2=12
5+7+2=14
3+9+6=18
4+2+7=13
6+7+1=14
2+6+4=12
Here we can see that all the results are even except
4+2+7
that is 13.
Hence the answer will be 427 (b). - 10 years agoHelpfull: Yes(6) No(0)
- b.427 is the answer
as in this three digit no.
sum of 1st digit and 3rd digit is not equal to 2nd digit.. - 9 years agoHelpfull: Yes(3) No(0)
- 462-396=66 , 66 can divisible by 11
572-462=110, 110 can divisible by 11
396-572=-176 , 176 can divisible by 11
427-396=31 not possible by 11
671-427=244 not possible by 11
264-671=-407, can divisible by 11,
here 427 is odd out.
- 9 years agoHelpfull: Yes(2) No(2)
- 427
middle no=sum of othr two - 9 years agoHelpfull: Yes(1) No(0)
- Simply divide by 11 and check
which is not divisible bu 11 is ans (427) - 9 years agoHelpfull: Yes(0) No(0)
- 427 is the correct answer...........
- 9 years agoHelpfull: Yes(0) No(0)
- 427 because 4+7 !=2
- 9 years agoHelpfull: Yes(0) No(0)
- option b. that is 427 is the odd number.
because sum of the digits is odd number.
for remaining numbers sum of the digits is even number. - 9 years agoHelpfull: Yes(0) No(0)
- Sum of 1st and last digits equals the middle one.
i.e.
396: 3+6=9
427: 4+2=6
572: 5+2=7
396: 3+6=9
427: 4+7=11 (not correct) odd one
671: 6+1=7
264: 2+4=6 - 9 years agoHelpfull: Yes(0) No(0)
- ans is 264 bcoz every time it repeats after 2 elements
- 8 years agoHelpfull: Yes(0) No(0)
- 427 is the correct answer
- 8 years agoHelpfull: Yes(0) No(0)
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