How many candidates were interviewed everyday by the panel A out of the three panels A, B and C?
I.The three panels on average interview 15 candidates every day.
II.Out of a total of 45 candidates interviewed everyday by the three panels, the number of candidates interviewed by panel A is more by 2 than the candidates interviewed by panel c and is more by 1 than the candidates interviewed by panel B.

A. I alone sufficient while II alone not sufficient to answer B. II alone sufficient while I alone not sufficient to answer
C. Either I or II alone sufficient to answer D. Both I and II are not sufficient to answer
E. Both I and II are necessary to answer

• OPT 2 is alone enough as it has mentioned the avg candidate/day and relation with other panels.
  let x be the number of candidate interviewed by A.
  => x+x-1+x-2=45
  3x=48
  x=16
  so panel A interviewed 16 candidates/day
• 11 years agoHelpfull: Yes(19) No(0)
• op E!!!
  from 1)A+B+C=45
  from 2)A=C+2 and A=B+1
  so both are required:)
• 12 years agoHelpfull: Yes(1) No(11)
• a+b+c=15*3=45
  a=c+2
  a=b+1 so e is the answer
• 11 years agoHelpfull: Yes(1) No(3)
• I. Total candidates interviewed by 3 panels = (15 x 3) = 45.
  
  II. Let x candidates be interviewed by C.
  
  Number of candidates interviewed by A = (x + 2).
  
  Number of candidates interviewed by B = (x + 1).
  
  x + (x + 2) + (x + 1) = 45
  
  3x = 42
  
  x = 14
  
  Hence, the correct answer is (B).
• 5 years agoHelpfull: Yes(0) No(0)