When two dice are thrown simultaneously, what is the probability that the sum of the two numbers that turn up is less than 11?

• total outcomes=6^2=36
  with 1 on one die possible outcomes=6
  with 2=6
  with 3=6
  with 4=6
  with 5=5
  with 6=4
  so total=6+6+6+6+5+4=33
  so 33/36
• 12 years agoHelpfull: Yes(14) No(3)
• Answer is 11/12.
  
  Total thrown chance are 6*6=36
  
  possible counts are (1,1),(1,2)..(1,6)=6
  and (2,1),(2,2)...(2,6)=6
  and (3,1),(3,2)...(3,6)=6
  and (4,1),(4,2)...(4,6)=6
  and (5,1),(5,2)...(5,5)=5..because(5,6) will be 11 and we need less than 11..so
  and (6,1),(6,2),(6,3),(6,4)=4
  
  
  so total possible chances are 6+6+6+6+5+4=33 out of 36
  
  so 33/36=11/12
  and (3,1),(3,2)...(3,6)=6
• 11 years agoHelpfull: Yes(10) No(0)
• alternately, sum of the two nos is >= 11 for (5,6),(6,5),(6,6).
  
  so probability of getting the sum >= 11 is 3/36.
  
  or probability of getting the sum
• 9 years agoHelpfull: Yes(4) No(0)
• alternately, sum of the two nos is >= 11 for (5,6),(6,5),(6,6).
  
  so probability of getting the sum >= 11 is 3/36.
  
  or probability of getting the sum
• 9 years agoHelpfull: Yes(0) No(0)