IBM Company Numerical Ability Probability

A number is selected at random from first thirty natural numbers. What is the chance that it is a multiple of either 3 or 13?

Read Solution (Total 2)

the 1st 30 natural nums are 1...30
inthat multiple of 3 0r 13
then the multiples of 3 or13 are =3,6,9,12,15,18,21,24,27,30 and 13,26=12
probability =12/30=2/5
12 years agoHelpfull: Yes(27) No(1)

Multiple of 3=3,6,9,12,15,18,21,24,27,30
Multiple of 13=3,26
Total of all multiple is 12, therefore the probability is:
12/30=2/5
11 years agoHelpfull: Yes(3) No(0)

IBM Other Question

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