Two dice are thrown together. What is the probability that the sum of the numbers on the two faces is divisible by 4 or 6?
A. 5/18 B. 7/18
C. 9/18 D. 12/18

• n(s)= 6^2=36
  let E be the event such that the sum of the numbers is divisible by 4 or 6
  E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}
  therefore n(E)=14
  p(E)=n(S)/n(E)=14/36=7/18
• 12 years agoHelpfull: Yes(22) No(2)
• n(S)=6*6=36
  no. of set, sum div by 4 or 6 are (1,5),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(6,2),(1,3),(3,3),(4,4),(5,3)
  n(E)=14
  P=14/36=7/18
  'B' is ri8.
• 12 years agoHelpfull: Yes(4) No(2)
• answer will be 7/18 (b)
• 9 years agoHelpfull: Yes(0) No(1)
• B. 7/18
  14/36
• 8 years agoHelpfull: Yes(0) No(1)
• 7/18
  9/36+6/36-1/36
• 8 years agoHelpfull: Yes(0) No(1)