In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?
A. 1/4 B. 1/6
C. 7/12 D. 5/36

• two dice are thrown the outcomes are 6^2=36 ways
  getting of a total 10 or 11 are (4,6),(5,5),(5,6)(6,4),(6,5)
  i.e., 5 ways
  so the probability of getting total of 10 or 11 is=5/36
  option 4 is ans
• 12 years agoHelpfull: Yes(51) No(1)
• ans is 5/36
• 12 years agoHelpfull: Yes(12) No(0)
• two dice are thrown the outcomes are 6^2=36 ways
  getting of a total 10 or 11 are (4,6),(5,5),(5,5),(5,6)(6,4),(6,5)
  i.e., 6 ways
  so the probability of getting total of 10 or 11 is=6/36=1/6
  option 2 is ans
• 12 years agoHelpfull: Yes(5) No(30)
• 5/36..
  The possibilites if sum 10 or 11 are (5,5),(6,4)(4,6)(6,5)(5,6)
  P(E)=5
  P(s)=36
  P(10 or 11)=5/36..
  
• 10 years agoHelpfull: Yes(3) No(0)
• two dice are thrown the outcomes are 6^2=36 ways
  getting of a total 10 or 11 are (4,6),(5,5),(5,5),(5,6)(6,4),(6,5)
  i.e., 6 ways
  so the probability of getting total of 10 or 11 is=6/36=1/6
  option 2 is ans
• 12 years agoHelpfull: Yes(2) No(23)
• correct ans. is 5/36.
  (5,5) is counted only once
• 7 years agoHelpfull: Yes(2) No(0)
• two dice thrown i.e 6*6=36
  we can't get sum 10 with 1,2,3 now lets try with 4,5,6
  (4,6)(5,5)(5,6)(6,4)(6,5) i.e 5 ways
  ans is 5/36
• 7 years agoHelpfull: Yes(2) No(0)
• two dice are thrown the outcomes are 6^2=36 ways
  getting of a total 10 or 11 are (4,6),(5,5),(5,5),(5,6)(6,4),(6,5)
  i.e., 6 ways
  so the probability of getting total of 10 or 11 is=6/36=1/6
  option 2 is ans
• 12 years agoHelpfull: Yes(1) No(25)
• correct ans is D. 5/36
• 9 years agoHelpfull: Yes(1) No(0)
• n(e)=6*6=36
  n(s)=(4,6),(5,5),(5,6),(6,5),(6,4),(6,6)
  N(s)/n(e)=1/6
• 7 years agoHelpfull: Yes(0) No(4)
• D (4,6;6,4;5,5;6,5;5,6
• 7 years agoHelpfull: Yes(0) No(0)
• for two dices thrown is 36 and probability for getting 10 or 11 is 6+4,4+6,5+5,6+5,5+6
  so 5/36
• 6 years agoHelpfull: Yes(0) No(0)
• the answer is (D) 5/36.
• 5 years agoHelpfull: Yes(0) No(0)
• p(E)=n(E)/n(S)
  getting total of 10 or 11 from throwing two dice are (5,5),(5,6),(6,5),(6,4),(4,6)
  so, no.of required events are 5 and total sample space is 36.So 5/36.
• 5 years agoHelpfull: Yes(0) No(0)