IBM
Company
Numerical Ability
Probability
In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?
A. 1/4 B. 1/6
C. 7/12 D. 5/36
Read Solution (Total 14)
-
- two dice are thrown the outcomes are 6^2=36 ways
getting of a total 10 or 11 are (4,6),(5,5),(5,6)(6,4),(6,5)
i.e., 5 ways
so the probability of getting total of 10 or 11 is=5/36
option 4 is ans - 13 years agoHelpfull: Yes(51) No(1)
- ans is 5/36
- 13 years agoHelpfull: Yes(12) No(0)
- two dice are thrown the outcomes are 6^2=36 ways
getting of a total 10 or 11 are (4,6),(5,5),(5,5),(5,6)(6,4),(6,5)
i.e., 6 ways
so the probability of getting total of 10 or 11 is=6/36=1/6
option 2 is ans - 13 years agoHelpfull: Yes(5) No(30)
- 5/36..
The possibilites if sum 10 or 11 are (5,5),(6,4)(4,6)(6,5)(5,6)
P(E)=5
P(s)=36
P(10 or 11)=5/36..
- 11 years agoHelpfull: Yes(3) No(0)
- two dice are thrown the outcomes are 6^2=36 ways
getting of a total 10 or 11 are (4,6),(5,5),(5,5),(5,6)(6,4),(6,5)
i.e., 6 ways
so the probability of getting total of 10 or 11 is=6/36=1/6
option 2 is ans - 13 years agoHelpfull: Yes(2) No(23)
- correct ans. is 5/36.
(5,5) is counted only once - 8 years agoHelpfull: Yes(2) No(0)
- two dice thrown i.e 6*6=36
we can't get sum 10 with 1,2,3 now lets try with 4,5,6
(4,6)(5,5)(5,6)(6,4)(6,5) i.e 5 ways
ans is 5/36 - 8 years agoHelpfull: Yes(2) No(0)
- two dice are thrown the outcomes are 6^2=36 ways
getting of a total 10 or 11 are (4,6),(5,5),(5,5),(5,6)(6,4),(6,5)
i.e., 6 ways
so the probability of getting total of 10 or 11 is=6/36=1/6
option 2 is ans - 13 years agoHelpfull: Yes(1) No(25)
- correct ans is D. 5/36
- 10 years agoHelpfull: Yes(1) No(0)
- n(e)=6*6=36
n(s)=(4,6),(5,5),(5,6),(6,5),(6,4),(6,6)
N(s)/n(e)=1/6 - 8 years agoHelpfull: Yes(0) No(4)
- D (4,6;6,4;5,5;6,5;5,6
- 7 years agoHelpfull: Yes(0) No(0)
- for two dices thrown is 36 and probability for getting 10 or 11 is 6+4,4+6,5+5,6+5,5+6
so 5/36 - 7 years agoHelpfull: Yes(0) No(0)
- the answer is (D) 5/36.
- 6 years agoHelpfull: Yes(0) No(0)
- p(E)=n(E)/n(S)
getting total of 10 or 11 from throwing two dice are (5,5),(5,6),(6,5),(6,4),(4,6)
so, no.of required events are 5 and total sample space is 36.So 5/36. - 6 years agoHelpfull: Yes(0) No(0)
IBM Other Question