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Numerical Ability
Permutation and Combination
How many words of 4 consonants and 3 vowels can be made from 12 consonants and 4 vowels, if all the letters are different?
Read Solution (Total 6)
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- 4 consonants out of 12 can be selected in 12C4 ways.
3 vowels can be selected in 4C3 ways.
Therefore, total number of groups each containing 4 consonants and 3 vowels = 12C4 * 4C3
Each group contains 7 letters, which can be arranging in 7! ways.
Therefore required number of words = 124 * 4C3 * 7! - 13 years agoHelpfull: Yes(49) No(4)
- Rqrd No. of words= 4P3 * 12P4 =285120
- 12 years agoHelpfull: Yes(6) No(24)
- 1980 words
- 13 years agoHelpfull: Yes(5) No(7)
- Total number of words possible=12C4 * 4C3
Total no of arrangements = 12C4 * 4C3 * 7! - 8 years agoHelpfull: Yes(5) No(0)
- Try this one...
Out of 12 consonants 4 consonants=12C4
Out of 4 vowels 3 vowels=4C3
Total group=12C4*4C3
Each group contains 7 letters,
SoTotal words=(12C4*4C3*7!)
=(495*4*5040)
=9979200 - 7 years agoHelpfull: Yes(3) No(1)
- 1980
12c4*4c3 - 8 years agoHelpfull: Yes(1) No(1)
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