Find the sum of roots for---sq root of(x+7)=x. sq root of(x+7)??? asked in e litmus 23rd nov 2014 @Bangaluru

• sqrt(x+7)-x*sqrt(x+7)=0
  sqrt(x+7)(1-x)=0 => x=-7 or 1
  squaring both sides
  x+7=x^2*(x+7)=>x^2=1 =>x=+-1
  thus the values of x are +1,-1,-7
  but if we put -1 the original equation we will get imaginary numbers which cant be compared thus we can say that there will be only 2 solution i.e x=1,-7
  so ans is -6
• 10 years agoHelpfull: Yes(18) No(1)
• I think ans will be -7
  
  sq root of (x+7) = x.sq root of (x+7)
  squaring both side, we get
  =>(x+7) = x^2 (x+7) // In eqn
  => x^2(x+7) - (x+7) = 0
  => (x+7) (x^2 -1) = 0
  so roots are= 1,-1,-7
  
  so sum of roots are = -7
• 10 years agoHelpfull: Yes(10) No(15)
• I think ans =0
  because as the eqn.....sq root of(x+7)=x. sq root of(x+7)..... is only satisfied by values of x=-1 and +1
  So the sum os roots =-1+1=0...
• 10 years agoHelpfull: Yes(2) No(3)
• answer will be -6
  Reason: sqrt(x+7) {+ve no.} = x. sqrt(x+7){+ve no.} thats mean either x must be +ve or x+7=0
  so only x=1 and (x+7 = 0) are possible solution
• 10 years agoHelpfull: Yes(1) No(0)
• after simplifying.....
  x+7=x2 (x+7)
  x2=1
  x=+-1
  sum of roots=0
• 10 years agoHelpfull: Yes(0) No(2)
• Sq.root(x+7)=x*Sq.root(x+7)
  taking squares on both sides
  (x+7)=x^2 *(x+7)
  (x+7)/(x+7) = x^2
  1=x^2
  + or - Sq.root(1)=x
  + or - 1=x
• 10 years agoHelpfull: Yes(0) No(3)
• sqr root of(x+7)=x.sqr root of(x+7)
  (x+7)=x^2(x+7)
  x^2=1
  then the result is +1 or -1
• 10 years agoHelpfull: Yes(0) No(2)
• sq root of (x+7) = x.sq root of (x+7)
  S.O .B.S
  (x+7)=x^2(x+7)
  => x^2=1
  => x=1,-1
  sum of roots=1-1
  =0
• 10 years agoHelpfull: Yes(0) No(1)
• the two roots are -7 and 1 so there sum is -6
• 9 years agoHelpfull: Yes(0) No(0)