How many four letter distinct initials can be formed using the alphabets of English language such that the last of the four words is always a consonant?

• we have to make distinct initials so we have the following choices...
  at last position=21 and this letter can not be repeated in remaining 3 positions:
  so answer is 25*24*23*21
• 12 years agoHelpfull: Yes(20) No(2)
• 
  The last of the four letter words should be a consonant. Therefore, there are 21 options.
  
  The first three letters can be either consonants or vowels. So, each of them have 26 options. Note that the question asks you to find out the number of distinct initials and not initials where the letters are distinct.
  
  Hence answer = 26*26*26*21 = 26^3 * 21
• 13 years agoHelpfull: Yes(14) No(11)
• The last of the four letter words should be a consonant - 21 options.
  The first three letters can be either consonants or vowels.
  so each of them have - 26 options
  Hence answer = 26*26*26*21 = 263 * 21 = 5523
• 12 years agoHelpfull: Yes(2) No(11)
• The last of the four letter words should be a consonant. Therefore, there are 21 options.
  
  The first three letters can be either consonants or vowels. So, each of them have 26 options. The question asks you to find out the number of distinct initials and not initials where the letters are distinct.
  
  Hence answer =26×26×26×21=26^3 ×21
• 11 years agoHelpfull: Yes(1) No(3)