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Numerical Ability
Permutation and Combination
In how many ways can the letters of the word EDUCATION be rearranged so that the relative position of the vowels and consonants remain the same as in the word EDUCATION?
Read Solution (Total 3)
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- There are 5 vowels and 4 consonants so total no of methods on the basis of given conditions are (5*4*3*2*1)*(4*3*2*1) = 120*24 = 2880
rearrangment =2880-1=2879 - 11 years agoHelpfull: Yes(4) No(5)
- 5 vowels, 4 consonants in the word EDUCATION.
5 vowels can be placed at 5 different places, and 4 different consonants can be placed at 4 different places.
so 1st vowels can be placed at the following places means 5 choices it has _D_C_T_ _N
then 2 nd vowel has 4 choices, n 3rd will have 3 choices,
same for consonants,
so letters that can be formed are 5!*4!
120*24
2880 - 9 years agoHelpfull: Yes(3) No(0)
- here there are 5 vowels and 4 consonants so
4 vowels + 1 pack of vowels
5 letters
inside the pack of vowels it can come in 5! ways
so 5!*5! will be the answer - 9 years agoHelpfull: Yes(1) No(3)
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