Printer A prints 8192 character per min and printer B prints 13862 character per min four character ar e equal to one word. Printer A starts at 7:15 am while Printer B starts at 7:29 am then at what time both will have same no of words printed .

• "four character are equal to one word"
  8192/4*(t+14)=13862/4*t
  8192*(t+14)=13862*t yields the same result
  t=20.2272 minutes = about 20 min 14 sec
  7:49:14 am
• 12 years agoHelpfull: Yes(62) No(5)
• In every min, Printer B will print 5670 characters extra. It is lagging behind printer A by 8192*14 characters.
  
  It will cover this gap in 8192*14/5670 mins or approx 23 mins. So at 7:52 both will have same no of words printed .
• 14 years agoHelpfull: Yes(18) No(23)
• (8192)*(t+14)=13862*(t)
  by simplyfying
  t=21.28712 minutes= about 21 min 29 sec
  7:50:29 am
• 10 years agoHelpfull: Yes(7) No(6)
• why ( t+14)
  is
• 9 years agoHelpfull: Yes(5) No(0)
• pls any one give explanation..
• 10 years agoHelpfull: Yes(3) No(0)
• same as below explanation
  here we take (t+14) because we are having the time difference 14 (i.e 7.29-7.15)
  
• 9 years agoHelpfull: Yes(2) No(1)
• A started 14 min before B started printing.
  so A can print (14*8192 characters) *(1/4) words.
  B can print faster than A. (so here u can apply relative motion like method. )
  B can print 5670/4 words more than A every min .
  so, B will take (8192/4)*14 / (5670/4) mins to print same number of words as A
  
• 9 years agoHelpfull: Yes(0) No(0)
• (8192)*(X+14)=13862*(X)
  X=21.28min
  21min 29 sec
  7:29+0:21:29
  =7:50:29
• 9 years agoHelpfull: Yes(0) No(4)