What was the day of the week on 17th June, 1998?

A. Monday B. Tuesday
C. Wednesday D. Thursday

• 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
  
  Odd days in 1600 years = 0
  
  Odd days in 300 years = (5 x 3) 1
  
  97 years has 24 leap years + 73 ordinary years.
  
  Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.(just divide 97 by 4---the quotient is the no. of leap years and (let x) and (97-x) is the no. of ordinary years.)
  
  Jan. Feb. March April May June
  (31 + 28 + 31 + 30 + 31 + 17) = 168 days
  
  168 days = 24 weeks = 0 odd day.
  
  Total number of odd days = (0 + 1 + 2 + 0) = 3.
  
  Given day is Wednesday.
• 12 years agoHelpfull: Yes(7) No(5)
• c) wednesday was the day of the week on 17th June, 1998
• 12 years agoHelpfull: Yes(3) No(9)
• 1.1.2001 is Monday as per calendar.
  1.1.2000 is Saturday
  1.1.1999 is Friday(Jan 31 days = 4 weeks + 3 odd days and so on for every month)
  
  1.1.1998 is Thursday
  Jan+Feb+mar+apr+may+jun(17 days) = 3+0+3+2+3+3+3 = 17/7 => Remainder = 3.
  For 3 as per the table it is Wednesday.
  Answer is Wednesday.
• 9 years agoHelpfull: Yes(0) No(0)
• the answer is thrusday.
• 4 years agoHelpfull: Yes(0) No(0)