A company contracts to paint 3 houses. Mr. Brown can paint a house in 16 days while Mr. Black would take 18 days and Mr. Blue 12 days. After 8 days Mr. Brown goes on vacation and Mr. Black begins to work and he leaves after working for 6 days. How many days will it take Mr. Blue to complete the remaining part of the contract?
A. 7
B. 2
C. 4
D. 8
E. 6

• A-16days
  B-18days
  C-12days
  According to question
  (8/16)+(6/18)+(x/12)=1
  =>(1/2)+(1/3)+(x/12)=1
  So x will be 2
  Ans 2
• 9 years agoHelpfull: Yes(8) No(2)
• sol…since the time for painting 1 house is given so multiply each by3
  Now simply time for each let say A, B,C becomes 18 24 and 36… days respectively so the eqn for total work could be simply framed as 8/18+6/24+x/36=1( assuming x as the time fo mr Blue…solve to get 11 as answer:)
  
  
• 10 years agoHelpfull: Yes(4) No(3)
• A-1day work = 1/6
  B-1day work = 1/8
  C-1day work = 1/12
  A+B+C (work) ==> 8/6+6/8+x/12 = 3
  Answer::x=11
  
• 9 years agoHelpfull: Yes(4) No(2)
• A-6 days (1/6 work in 1 day)
  B-8 days (1/8 work in 1 day)
  C-12 days (1/12 work in 1 day)
  
  From the question:
  (8/6)+(6/8)=(x/12) = 3
  
  x = 11 Days
• 12 years agoHelpfull: Yes(3) No(10)