A cricketer has a certain average for 9 innings. In the tenth he scores 50, thereby increasing his average by 4 runs. What is his new average?
A. 6
B. 10
C. 14
D. 16
E. 8

• lets average for 9 innings=x
  then
  (9*x +50)/10=x+4
  9x+50=10x+40
  x=10
  
  so 9 innings average = 9*10
  10 innings=90+50/10
  =14
• 9 years agoHelpfull: Yes(1) No(0)
• average for 9th innings be x;
  score in 10th match=10*(x+4)-9*x;
  =>50=10x+40-9x;
  =>x=10;
  option b is correct
• 9 years agoHelpfull: Yes(1) No(0)
• C.14
  9 ININ 10 =========== 90 RUNS
  10 ININ 14 =========== 140 RUNS
  DIFFERENCE = 50 IN 10 TH INNINGS
  SO NEW AVERAGE = 14
• 9 years agoHelpfull: Yes(0) No(0)
• pls explain?
• 9 years agoHelpfull: Yes(0) No(0)
• In 10 inning avg.=x
  9th inning avg.=x-4
  9(x-4)+50=10X
  so, x=14
  
• 9 years agoHelpfull: Yes(0) No(0)