11+22+33+...+1010 is divided by 5. What is the remainder?

• 11+22+33+......+1010
  11(1+2+3+....9)+1010
  11*45+1010
  495+1010
  1505
  
  1505%5=0 is reminder
• 9 years agoHelpfull: Yes(17) No(1)
• I think this series is 11+22+33+44.....+99+1010
  (22+33)%5=0
  55%5=0
  (44+66)%5=0
  (77+88)%5=0
  (11+99)%5=0
  1010%5=0......so the remainder is 0
• 9 years agoHelpfull: Yes(5) No(0)
• 11+22+33+..+99=459 and 459+1010=1505 which gives reminder 0
• 9 years agoHelpfull: Yes(3) No(0)
• 11/5 = 1
  (22+33)/5 = 0
  (44+66)/5 = 0
  55/5 = 0
  (77+88)/5 = 0
  .
  .
  .
  .
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  1010/5 = 0
  => 1 is the remainder (11/5)
• 9 years agoHelpfull: Yes(1) No(2)
• When a whole number is divided by 5, the remainder depends on the units digit of thatnumber.Thus, we need to determine the units digit of the number 1
  1
  +2
  2
  +3
  3
  +...+10
  10
  . To do so, weneed to first determine the units digit of each of the individual terms in the expression asfollows:Term Last (Units) Digit1
  1
  
  1
  2
  2
  
  4
  3
  3
  
  7
  4
  
  4
  
  6
  5
  
  5
  
  5
  6
  6
  
  6
  7
  7
  
  3
  8
  8
  
  6
  9
  9
  
  9
  10
  10
  
  0
  To determine the units digit of the expression itself, we must find the sum of all the unitsdigits of each of the individual terms:1 + 4 + 7 + 6 + 5 + 6 + 3 + 6 + 9 = 47
  
  
  
  
  Thus,
  7
  is the units digit of the number 1
  1
  +2
  2
  +3
  3
  +...+10
  10
  . When an integer that ends in 7is divided by 5, the remainder is 2. (Test this out on any integer ending in 7.)
• 9 years agoHelpfull: Yes(1) No(2)
• 11+22+33+......+1010
  11(1+2+3+....9)+1010
  11*45+1010
  495+1010
  1505
  
  1505%5= 0
• 9 years agoHelpfull: Yes(1) No(0)
• remainder is 0
  1010 is divisible by 5 so the remainder is 0
• 9 years agoHelpfull: Yes(1) No(0)
• 1010/5=202 so remainder is 0
• 9 years agoHelpfull: Yes(0) No(4)
• 1010/5=202..there is no remainder
• 9 years agoHelpfull: Yes(0) No(3)
• what about remaining @satrasala siva charan?
• 9 years agoHelpfull: Yes(0) No(0)
• may be 2
  it is in ap
  sum is 21252
  den 21252/5 gives remainder 2
• 9 years agoHelpfull: Yes(0) No(1)
• sum of numbers = 54945(by using formula s=n/2(2a+(n-1)d)
  54945/5
  remainder=0
• 9 years agoHelpfull: Yes(0) No(1)
• 0
  the last digits of numbers in the series will result in 0 in units place so it will be divisible by 5
• 9 years agoHelpfull: Yes(0) No(0)