Wipro
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Numerical Ability
Geometry
A polygon has 44 diagonals. Number of sides=?
A. 7
B. 11
C. 8
D. 9
E. 10
Read Solution (Total 2)
-
- B.11
no. of diagonals=[n(n-3)]/2
n=no. of sides
44=(n2-3n)/2
n2-3n-88=0
n2-11n+8n-88=0
n=11 - 10 years agoHelpfull: Yes(12) No(0)
- nc2-n=44(using formula)
so from the ans
subs 11
11*10/1*2-11=44 - 8 years agoHelpfull: Yes(2) No(0)
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