a,b,c in gp and mno in ap
value of---(o-n)log a+(o-m)log b+(n-m)log c
1-(o-n)logabc
2--1
3--0

• (o-n)log a + (o-m) log b + (n-m)log c
  = o(log a + log b) + n(log c - log a) - m(log b + log c)
  
  since m,n,o in ap, therefore m= 2n - o
  o(log a + log b) + n(log c - log a) - (2n- o)(log b + log c)
  = olog a + olog b + nlog c - nlog a - 2nlog b - 2nlog c + olog b + olog c
  =o[loga +2logb + logc] - n[loga +2logb +logc]
  =(o-n)[loga + 2logb + logc
  =(o-n) [ loga + 2logb + log(b^2/a)] since a,b,c are in gp, therefore c=b^2/a
  =(o-n) [ loga+ 2logb +2logb -log a]
  =(o-n) 4logb
  =(o-n) log b^4
  =(o-n) log b^2 logb^2
  
  =(o-n) logb^2 logac
  =(o-n) 2logb logac
  =(o-n) 2 logabc
  
• 10 years agoHelpfull: Yes(3) No(2)
• Answer
  (o-n)log abc
• 10 years agoHelpfull: Yes(0) No(0)
• can you explain briefly
• 10 years agoHelpfull: Yes(0) No(0)
• @amit
  can u explain which property u applied on second last statement to get answer
• 9 years agoHelpfull: Yes(0) No(0)