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Two liquids are mixed in the proportion of 3:2 and the mixture is sold at $11 per litre at a 10% profit. If the first liquid costs $2 more per litre than the second, what does it cost per litre?
A. $10.30
B. $10.60
C. $10.40
D. $10.20
E. $10.80
Read Solution (Total 1)
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- Here the ratio is given as 3:2
from the mixtures:
suppose second liquid is x,then first liquid is x+2
x-10/10-x-2 = 3/2
2x-20 = 24-3x
5x = 44
x=8.8
so first liquid cost is x+2 = 8.80+2 = 10.80 - 10 years agoHelpfull: Yes(1) No(1)
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