In an election contested by two parties, Party D secured12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?
A. 24,000
B. 36,000
C. 168,000
D. 300,000
E. 20,000

• Let total % of votes secured by D = x
  Therefore, by R = ( x - 12)%
  As there are only two parties,
  Thus,
  x + (x - 12) = 100
  x = 56%
  Therefore, R got (56 - 12) = 44%
  By question, R got = 132,000
  i.e; 44% (T) = 132,000
  T = 3000,00
  Now, Party R lost by 12% (T)
  = 36,000
  
  
• 10 years agoHelpfull: Yes(7) No(3)
• Let the percentage of the total votes secured by Party D be x%
  Then the percentage of total votes secured by Party R = (x – 12)%
  
  As there are only two parties contesting in the election, the sum total of the votes secured by the two parties should total up to 100%
  
  i.e., x + x – 12 = 100
  2x – 12 = 100
  or 2x = 112 or x = 56%.
  
  If Party D got 56% of the votes, then Party got (56 – 12) = 44% of the total votes.
  
  44% of the total votes = 132,000
  i.e., = 132,000
  ð T = = 300,000 votes.
• 11 years agoHelpfull: Yes(5) No(3)