a,b,c,d are prime number. how many combintion of prime numbers can be possible such that the sum of two digit(a+b,a+c,a+d,....)..And the sum in increasing order are 2,4,6,8...

option-- 1 only 2 only 4 only more than 4

• 2 only is right
  2,3,5,7,11,13,17,19
  2+3=5
  2+5=7
  2+7=9
  5,7,9 has succesive increase of 2
  so only two combination possible 5-7,7-9
  after that 11,13,17,......... has not succesive increse of two
  so two is the right ans
  
• 10 years agoHelpfull: Yes(9) No(3)
• more than 4
• 10 years agoHelpfull: Yes(0) No(6)
• (1,1,3,5) is the possible combination
  therefore 4!/2! = 12
  so more than 4 may be the correct answer
• 10 years agoHelpfull: Yes(0) No(18)
• more than 4
  (2,5,7,11),(3,5,7,11),(5,11,13,17),(7,11,13,17),(11,17,19,23)..... combinations are possible
• 10 years agoHelpfull: Yes(0) No(1)
• only 2 combination of prime numbers are enough.....2,3,5,7,11,13,17,19....
  2,4,6,8=the difference b/w alternate 2 numbers are 2.....SO
  let us take=2+3=5
  2+5=7
  2+7=9...
  the difference is 2...
  and next...let us take 4 prime numbers like=2+3+5+7=17
  3+5+7+11=26
  5+7+11+13=36
  so difference is not 2 and difference is not same b/w 2 numbers ...
  so answer is 2....i think
• 10 years agoHelpfull: Yes(0) No(1)
• only 1....
  
  
  2,3,5,7
  
  2+3=5
  2+5=7
  2+7=9
  ....
  
  @ashu 5,7,9 ...bro when did 9 became a prime no ?
• 9 years agoHelpfull: Yes(0) No(0)
• @ ashu kaushal stupid answer
• 5 years agoHelpfull: Yes(0) No(0)