There are 2 printers installed to print some pages. If you have to find out how many pages will the printers print at 35°C when one

printer’s work is directly proportional and the others printer work is inversely proportional to the temperature and the total work done at 15°C is

20 pages and that done on 20°C is 25 pages?

a. 40 pages
b. 41.2 pages
c. 40.7 pages
d. 43.2 pages
e. 39.7 pages

• b. 41.2
  
  If 1st Printer works directly proportional to the temperature with constant K1 and
  2nd printer works inversely proportional to the temperature with constant K2, then
  Pages printed at particular temperature= T1*K1 + K2/T2 ----(i)
  15K1+ (K2/15) = 20 ----(ii) &
  20K1+ (K2/20) = 25 ----(iii)
  On solving (ii) & (iii), K1=8/7 ,K2=300/7
  From (i), Total pages printed at 35°C = (35*8/7) + [300/(7*35)] =40 + (60/49)= 41.22
• 10 years agoHelpfull: Yes(16) No(0)
• @devendra pls slove this too
  A cask of wine when fully filled holds 10 liters. 2 liters of wine is removed and filled with water. Then 4 liters in the solution is replaced with water. Then 6 and 8 liters respectively. At the end of the 4th operation , the ratio of wine to water is.
  A. 4! / (5) 4
  B. 4! / (5 4 - 4! )
  C. 8! / 10 4
  D. 8! / (10 4 – 8! )
  E. None
• 10 years agoHelpfull: Yes(15) No(0)
• thnku so much @devendra pls help me with the last one
  
  What is the probability of a/b will be an integer when a=2x3y and b=2l3m and all of x, y, I, m are positive integers?
  
  a. 1/6
  b. 2/3
  c. 1/2
  d. 1/4
  e. 3/4
  
  
  
• 10 years agoHelpfull: Yes(12) No(2)
• B. 4!/(5^4 - 4!)
  
  1. 1st removal of 2 lit. of wine from 10 liters & when replaced with 2 lit. of water, result in to ratio of wine/ water=(10-2) /2 = 8/2
  
  2. 2nd removal of 4 lit. of mixture from 10 liters & when replaced with 4 lit. of water, result in to removal of Qty. of wine=4*8/10=16/5 & water =4*2/10=4/5,
  So Remaining wine=8 -(16/5)= 24/5 & Water=10- (24/5)= 26/5
  
  3. 3rd removal of 6 lit. of mixture from 10 liters & when replaced with 6 lit. of water, result in to removal of Qty. of wine=6*(24/5)/10=72/25 & water=6*(26/5)/10=39/5
  So Remaining wine=(24/5) - (72/25)=48/25 & water=10 -(48/25) =202/25
  
  4. 4th removal of 8 lit. of mixture from 10 lit. & when replaced with 8 lit. of water, result in to
  removal of Qty. of wine=8*(48/25)/10= 192/125
  So remaining wine=(48/25) - (192/125)= 48/125 & water= 10- (48/125)= 1202/125
  
  So ratio of Wine to Water =(48/125) / (1202/125) = 24/601
  From the given option B. 4!/(5^4 - 4!)= 24/(625 -24) =24/601 is correct
• 10 years agoHelpfull: Yes(9) No(0)