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A hollow space on earth surface is to be filled. Total cost of filling is Rs20000. The cost of filling per mt3 is Rs 225 .how many times a size of 3 mt3 soil is required to fill the hollow space?
Read Solution (Total 2)
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- it costs 225 for 1mt3
given total cost is 20000
so the total volume is 20000/225=88.888
v need to calculate the no of times of 3mt3
so,88.888/3=29.62
therefore 29.62times a size of 3mt3 soil is required - 14 years agoHelpfull: Yes(30) No(0)
- The above answer is ryt still i will solve ...
Change mt3 to packet(fo understanding)
Cost 20000
Per packet 225
No of packet 20000/225=88.88
More size of the packet : Less packet required (inverse relation)
. SIZE. |. PACKET
. 1. |. 88.88
. 3. |. 88.88/3= 29.62
STILL THANKS TO ABOVE PERSON. - 10 years agoHelpfull: Yes(2) No(0)
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