A man driving his bike at 24 kmph reaches his office 5 minutes late. Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time. How far is his office?

(1) 24 km
(2) 72 km
(3) 18 km
(4) Data Insufficient

• x/24 - x/30 = 9/60
  
  x = 18km
• 12 years agoHelpfull: Yes(7) No(0)
• initial speed 24kmph
  +25% speed = 30kmph
  speed ratio 24:30 = 4: 5
  time 5:4 (as time is inversly propertional to speed)
  so 5 - 4 = 1hr = 60 mins late when dist is lcm(24,30)=120 km
  (4+5)=9mins late when dist is = (120*90)/60 = 18 km
• 6 years agoHelpfull: Yes(1) No(0)
• Answer is 18KM.
  D is the distance to office And t is Actual time
  driving his bike at 24 kmph reaches his office 5 minutes late.
  D=(t+5)*24/60
  Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time means
  25% more speed means the new Speed is 30kmph
  D=(t-4)*30/60.
  
  Solving these two equations, D comes as 18km.
• 13 years agoHelpfull: Yes(0) No(0)
• Let x km be the distance between his house and office.
  While travelling at 24kmph, he would take
  x 24 hours.
  While travelling at 25% faster speed,
  24+25% of 24=24×(
  1
  4
  )=30 kmph, he would take
  x
  30
  hours.
  
  Now as per the problem, time difference = 5 min late + 4 min early = 9 min
  ⇒
  x
  24
  −
  x
  30
  =9 min
  ⇒ x= 18 km
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)