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A sum of 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of 362.50 more is lent but at the rate twice the former. At the end of the year, 33.50 is earned as interest from both the loans. What was the original rate of interest?
3.6%
4.5%
5%
6%
None of these
Read Solution (Total 1)
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- si=p*t*r/100
using this formula
si1+si2=(p1*t1*r/100)+(p2*t2*2r/100)
si1+si2=33.50
p1=725
t1=1 years
p2=362.50
t2=0.33 yrs
putting these values we wil get r=3.45 - 12 years agoHelpfull: Yes(1) No(2)
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