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Maths Puzzle
Numerical Ability
Number System
10,11,14,23,.......,131
what is the number in the ........?
Read Solution (Total 5)
-
- 50
10+ 3^0= 10+1= 11
11+ 3^1= 11+3= 14
14+ 3^2= 14+9= 23
23+ 3^3= 23+27=50
50+ 3^4= 50+81=131 - 10 years agoHelpfull: Yes(2) No(0)
- Answer = 50
The nth number in series is = (n-1)th number + pow(3,n-2) for n>=2
So, 2nd term = 10 + 1 = 11
3rd term = 11 + 3 = 14
4th term = 14 + 9 = 23
5th term = 23 + 27 = 50
6th term = 50 + 81 = 131 - 10 years agoHelpfull: Yes(0) No(0)
- ans 50
difference between 10&11 is 1=3^0
difference between 11&14 is 3=3^1
differeence between 14 &23 is 9=3^2
hence next difference is 3^3=27
hence no is 23+27=50
- 10 years agoHelpfull: Yes(0) No(0)
- 10 (1),11 (3),14 (9),23 (27), 50 (81), 131....hence 50 will be
- 10 years agoHelpfull: Yes(0) No(0)
- 11-10=1=3 power 0
14-11 = 3 = 3 power 1
23-14 =9
x-23=27
x=27+23=50
50+81=131 - 7 years agoHelpfull: Yes(0) No(0)
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