Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34

• If one got x marks , other got x+9 marks.
  
  x+9/ x = 56/44
  56x= 44 x + 396
  x= 396/ 12= 33
  
  so marks are 42 and 33.
• 12 years agoHelpfull: Yes(16) No(3)
• If one gets 56 % then other will get 44 %.
  As the difference in marks is of 56-44 = 12% which is 9
  So 12 % = 9
  100% = x
  
  x = 100*9/12
  
  First student marks = 100 * 9 * 56 / 12 * 100 =>> 42
  
  Second student marks = 100 * 9 * 44 / 12 * 100 =>> 33
• 9 years agoHelpfull: Yes(4) No(0)
• dipin hw can u calculate this using 396 where this is specified...
• 11 years agoHelpfull: Yes(2) No(3)
• Say one student gets x+9 and the other gets x.
  Then the statement translates to the following equation:
  x+9= 56/100(x+x+9)
  
  This is because the statement is talking about the person who scored 9 marks more, i., "his" (person with 9 marks more) marks was 56% of the sum of their marks.
  on solving... x+9=(112x + 504)/100
  Cross multiplying... 100x + 900 = 112x + 504
  Hence x=33
• 10 years agoHelpfull: Yes(2) No(0)
• Let the mark of one student=x
  and the mark of another one=x+9
  x+9=(x+x+9)*(56/100)
  after solving the eqution x=33
  so,ans 42,33
• 4 years agoHelpfull: Yes(0) No(0)