The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
1)-4.37%
2)-5%
3)-6%
4)-8.75%

• 5%
  
  Explanation:
  Increase in 10 years = (262500 - 175000) = 87500.
  Increase% = ( 87500 / 175000) x 100 % = 50%.
  average = 50/10 % = 5%.
  
  
  
• 13 years agoHelpfull: Yes(28) No(1)
• Approx 5%
  Increase in 10years is 87500.
  Increase per year is (87500)/10 = 8750
  Percentage increase = (8750/17500)*100 = 5%
• 9 years agoHelpfull: Yes(5) No(0)
• 8.75%
  Decade = 10years
  In 10 years, population inreased from 1,75,000 to 2,62500
  (i.eI inreased in 10years = 2,62,500 - 1,75,000
  =87500
  Therefore for 1 years, increase population = 87500/10
  =8750
  So, increasing percentage = 8.75%
• 13 years agoHelpfull: Yes(2) No(23)
• 4.37%
  
  Increase in 10 years = (262500 - 175000) = 87500.
  Therefore for 1 years, increase population = 87500/10
  =8750
  
  first year increase percentage=(8750/175000) x100=5%
  second year population =175000+8750=183750
  second year increase percentage=(8750/183750)x100=4.76%
  
  similarly for
  third year 4.54%
  fourth year 4.34%
  fifth year 4.16%
  sixth year 4%
  seventh year 3.84%
  eighth year 3.7%
  ninth year 3.57%
  tenth year 3.44%
  
  average we get 4.37%
• 7 years agoHelpfull: Yes(2) No(3)
• 2 is the answer i.e 5% because in 10 years the increase would be 50% so yearly increase would be 5%
• 7 years agoHelpfull: Yes(0) No(0)