TCS Company Numerical Ability Age Problem

There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability
A. P=1/3+(2/3*p^3)
B. P=2/3+(2/3*p^3)
C. P=2/3+(1/3*p^3)
D P=2/3+(2/3*p^3)

Read Solution (Total 10)

TCS Other Question

The bacteria has the probability of split into 3 and probability to die is 1/3rd of the total bacteria.Let the probability is P.Some of them survived with probability 1/5.Then which among the following relation is true?
a)P=1/3+1/5*3
b)P=1/5*(1/8-3)
Six friends decide to share a big cake. Since all of them like the cake, they begin quarreling who gets to first cut and have a piece of the cake. One friend suggests that they have a blindfold friend choose from well shuffled set of cards numbered one to six. You check and find that this method works as it should simulating a fair throw of a die. You check by performing multiple simultaneous trials of picking the cards blindfold and throwing a die. You note that the number shown by the method of picking up a card and throwing a real world die, sums to a number between 2 and 12. Which total would be likely to appear more often 8,9 or 10?
a) 8
b) All are equally likely
c) 9
d) 10