A ship went on a voyage after 180 miles a plane started with 10 times speed that of the ship. Find the distance when they meet from starting point.

• [Athira M. K.]
  Ans c) 200 miles.
  
  
  Let the distance traveled by the ship after 180 miles to meet the plane be 'd'
  Speed of the ship be 'x' and speed of the ship be '10x'
  
  Time taken by plane to travel 180+d dist. = time take by ship for 'd' dist.
  (180+d)/10x=d/x
  180+d=10d
  d=180/9=20.
  
  So the distance traveled when they meet from starting point=180+d=200 miles
• 11 years agoHelpfull: Yes(24) No(1)
• let u is the speed of ship and 10u is of plane.
  relative speed=9u
  distance covered=time to meet*speed of plane
  =180*10u/9u
  =200miles
• 11 years agoHelpfull: Yes(8) No(0)
• Let the speed of the ship = s miles/hr.
  
  and plane took 't' hours to meet the ship.
  
  Then, s×t is the distance ship traveled after plane started
  
  So we have, st + 280 = 15st⇒ st = 20
  
  Hence distance = 280 + 20 = 300 miles
• 4 years agoHelpfull: Yes(0) No(0)