The ratio between a two - digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit place is 3 more than the digit in the ten's place, what is that number ?

a. 24
b. 63
c. 36
d. None of these

• let the 2 digit number be 10a + b (i.e the number ab)
  so from the first relationship we can see that 10a+b=4(a+b)
  and from the second, b=a+3
  substituting the second into the first:
  10a+a+3=4(a+a+3)=11a+3=8a+12, 3a=9, a=3 (looking back at the equations), b=6
  so the number is 36
  
• 10 years agoHelpfull: Yes(3) No(1)
• 36
  
  sum is 9
  36:9
  =4:1
  
• 8 years agoHelpfull: Yes(1) No(1)
• Option verification
  Only one option satisfies that is d
  36/(3+6)=4:1 which satisfies 1st statement
  Ten digit place contains 3 so the unit place should be more than 3
  Therefore units place is 6 which is 3 more than tens digit which satisfies second statement
• 5 years agoHelpfull: Yes(0) No(0)
• unit digit is 3 more greter than the ten place so,in option 'c' unit digit is 3 more than tha tength place that is 6...so the ratio 36:(sum of 2 digit number)9=4:1
• 5 years agoHelpfull: Yes(0) No(0)
• From the options, the answer is 36. The unit’s digit is three more than ten’s digit. And 36:9= 4:1.
  So, Option c is correct answer
• 4 years agoHelpfull: Yes(0) No(0)