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In how many ways can 2, 3, 7 and 6 be arranged in a 4-digit number that is divisible by 3 using each digit only once?
a. 8
b. 12
c. 24
d. 256
Read Solution (Total 1)
-
- 4! =24
sum of all digits should be divisible by 3
18%3==0 - 6 years agoHelpfull: Yes(0) No(0)
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