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Basketball Tournament organizers decided that two consecutive defeats will knock out the team. There are 51 teams participating. What is the maximum no. of matches that can be played.
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- 101 matches....bcz for a match 2 teams reqd so 50*2 = 100 + 1 winner of finals
- 11 years agoHelpfull: Yes(5) No(1)
- Assuming there is no particular order and teams left standing play each other again until 2 defeats.
T1 can win 50 games in a row (don't play themselves). T2 - T51 have 1 defeat.
T2 can then win 49 games in a row (don't play themselves and have lost to T1). Every other team except T1 and T2 now have 2 defeats. -> T1=0 and T2=1
Team1 loses to T2 -> T1=1 and T2=1
Then either T1 or T2 loses.
Total = 50 + 49 + 1 + 1 = 101
#copied - 10 years agoHelpfull: Yes(5) No(1)
- 50
- 14 years agoHelpfull: Yes(2) No(3)
- 101 is the correct answer
- 10 years agoHelpfull: Yes(1) No(0)
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