Find three numbers in a GP whose sum is 26 and and product is 216

• 1. a+ar+ar^2 = 26
  2. a*ar*ar^2 = 216 => (ar)^3 = 216 => ar = 6
  Possible values of a,r pairs are (1,6) (2,3) (3,2) (6,1)
  Now, from 1, a+ar^2 = 26-6 = 20. So a=2, r=3
  Hence, the 3 numbers are 2, 6, 18
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