In an examination a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer

Let the number of correct answers be x
then numbers of incorrect answers will be 75-x
We get 4x-(75-x)= 125
On solving the equation we x= 40
12 years agoHelpfull: Yes(22) No(3)

logic wise:by trial and error method from options...
see b.40
if he attempts 40 qnos correctly.. then 40*4=160 marks
remaining questions is 75-40=35 wrong questions
so 35 mark minus for 35 wrong questions... 160-35=125..so answer is 40 :)
10 years agoHelpfull: Yes(12) No(1)
4x-1y=125
x+y=75
x=40,
9 years agoHelpfull: Yes(3) No(0)
let the number of correct answer is x
let the number of incorrect answer is 75 -x
so
4x-(75-x)=125
5x-75=125
5x=200
x=40 option :B
8 years agoHelpfull: Yes(2) No(0)
40*4-35*1=125
8 years agoHelpfull: Yes(1) No(0)
let the no. of correct ans. = X
no. of wrong ans. = (75-X)
then,
4X-(75-X)=125
5X=200
X=40
8 years agoHelpfull: Yes(1) No(0)
I have same explanation but i just want to clarify why are we subtracting (75-x) by 4x. My equation was 4x + (75-x)= 125, which is wrong. Can anyone please explain ?
11 years agoHelpfull: Yes(0) No(1)
ans is 40............
10 years agoHelpfull: Yes(0) No(1)
ans is 40
7 years agoHelpfull: Yes(0) No(0)
let correct answer=x
incorrect=75-x
4x-(75-x)=125
5x=200
x=40
5 years agoHelpfull: Yes(0) No(0)
total marks in paper 300 and the student secures 125 marks hence the student has answered 35 questions correctly.
answer a.35
5 years agoHelpfull: Yes(0) No(0)
40 qsns areattempted he will get 160 marks but 35 marks are tobe deducted for wrong ans so he will gain 125 marks
4 years agoHelpfull: Yes(0) No(0)
correct answer 40.
4 years agoHelpfull: Yes(0) No(0)

In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 75 questions and secures 125 marks, the number of questions he attempts correctly, is :

a. 35
b. 40
c. 42
d. 46